1^2-4^2/3-(-2)^2

Simple and best practice solution for 1^2-4^2/3-(-2)^2 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 1^2-4^2/3-(-2)^2 equation:


1^2-((4^2)/3)-(-2)^2 = 0

1-((4^2)/3)-(-2)^2 = 0

1-(16/3)-(-2)^2 = 0

1-(-2)^2-16/3 = 0

-(-2)^2-13/3 = 0

-13/3-4 = 0

-(4+13/3) = 0

-25/3 = 0

L <> R

See similar equations:

| 5+(-8)6=29 | | 1/3v-4=-1/2v-2/3 | | 3y-5+49=7y+50-5y | | 7-3x=x-4(2+2x) | | B=2500(1+.65)4 | | 1/3v-4=1/2v-2/3 | | 9x+44=4x+19 | | 12x^2=5x+9 | | 9u-28=-2(u-8) | | -4(x+2)-13=14+1 | | y=-.5x+300 | | -5y/9=-10 | | 4cox-3cosx-1=0 | | 6x-x+2x=28 | | 0.18(1/3) | | -7/9u=-28 | | Y+26=-51 | | 42-x=38 | | x(x-2)-x+2=0 | | n^2/4-9/4 | | -7/5v-3/2=2v-7/2 | | 5x^4-15x^2-4=0 | | 16=2(2w-w-1) | | 2/5y-2/3=-1/5y-2 | | sin(5x)+sin(x)-cos(4x)+cos(2x)=0 | | 6x+.80=22 | | 37=5-2x^2 | | 2/3*n=3/20 | | 3x(4-x)-17=x(x-3) | | 12x-16=-15x+17 | | 0.7t+0.9(12-t)=9.8 | | a/3-5=-9 |

Equations solver categories